Question

x-axis divides the line segment joining (2, - 3), (5, 2) in the ratio​

Answer 1

Step-by-step explanation:

Let the points be A(2,-3) , B(5,2) & (x,0) . Let the ratio be k:1 .

(x,y) = (m1x2+m2x1/m1+m2 , m1y2+m2y1/m1+m2)

= (k×5+1×2/k+1 , k×2+1×-3/k+1)

= (5k+2/k+1 , 2k-3/k+1)

This point lies on the axis & we know that on the x-axis the coordinate of y-axis is zero .

2k-3 = 0

k+1 1

Let's make cross multiplication

2k-3 = 0

2k = 3

k = 3

2

k = 1•5

=> So that the ratio is 1•5:1