x+b/a-b = x-b/a+b plz find the answer
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Given x+b/a-b = x-b/a+b can be written as
(x+b)(a+b) = (x-b)(a-b)
xa + xb + ab + b^2 = xa - bx - ba + b^2
xa + xb + ab + b^2 - xa + bx + ba - b^2
2xb + 2ab = 0
2b(x + a) = 0
x + a = 0
x = -a.
(x+b)(a+b) = (x-b)(a-b)
xa + xb + ab + b^2 = xa - bx - ba + b^2
xa + xb + ab + b^2 - xa + bx + ba - b^2
2xb + 2ab = 0
2b(x + a) = 0
x + a = 0
x = -a.
arsh54:
bhai 2b kahan gya?
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