Question

x^b+a. x^b+c . x^a+c / ( x^a . x^b . x^c ) ^2​

Answer 1

Given expression

(x

a

.x

b

.x

c

)

2

x

a+b

.x

b+c

.x

c+a

=x

a+b−2a

.x

b+c−2b

.x

c+a−2c

=x

b−a

.x

c−b

.x

a−c

=x

0

.

Answer 2

Answer:

0

Step-by-step explanation:

Given expression 

(xa.xb.xc)2xa+b.xb+c.xc+a

=xa+b−2a.xb+c−2b.xc+a−2c

=xb−a.xc−b.xa−c=x0.