Math, asked by DevanshVerma, 1 year ago

(x-b-c)/a+(x-a-c)/b+(x-a-b)/c

Answers

Answered by Anonymous
1
(x - b - c)/a + (x - a - b)/c + (x - c - a) / b = 3 
bc(x - b - c) + ab(x - a - b) + ac(x - c - a) = 3abc 
bcx - b²c - bc² + abx - a²b - ab² + acx - a²c - ac² = 3abc 
abx + bcx + cax = 3abc + a²b + ab² + b²c + bc² + a²c + ac² 
x(ab + bc + ac) = abc + a²b + ab²+ abc + b²c + bc²+ abc + a²c + ac² 
x(ab + bc + ac) = ab(c + a + b) + bc(a + b + c) + ac(b + a + c) 
x(ab + bc + ac) = (a + b + c)(ab + bc + ac) 
x = (a + b + c)(ab + bc + ac)/(ab + bc + ac) 
x = a + b + c
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Please mark the answer as brain list answer

DevanshVerma: correct
Answered by kinkymyke
0
incomplete question....
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