Math, asked by hdixit421, 7 months ago

(x-b-c)/a + (x-c-a)/b + (x-a-b)/c = 3
find the value of x?
from basic method. ​

Answers

Answered by sakshisingh27
8

Answer:

hi buddy here is your answer hope it will be helpful to you

Step-by-step explanation:

x-b-c)/a+(x-a-b)/c+(x-c-a)/b=3

Bc(x-b-c)+ab(x-a-b)+ac(x-c-a)=3abc

Bcx-b²c-bc² +abx- a²b -ab² +acx -a²c -ac²=3 abc

Abx+bcx +cax=3 abc+ a²b +ab²+ b²c+ bc²+ a²c+ ac²

X(ab+bc+ac)= abc+ a²b +ab²+ abc+ b²c +bc²+ abc +a²c +ac²

X(ab+bc+ac)=ab(c+a+b)+bc(a+b+c)+ac(b+a+c)

X(ab+bc+ac) =(a+b+c) (ab +bc+ ac)

X =(a+b+c) (ab+bc+ac)/(ab+bc+ac)

X=a+b+c

Hope this one is the correct ans.. !!

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