Question

x/b+c=y/c+a=z/a+bshow that(b-c)x+(c-a)y+(a-b)z=0​

Answer 1

Answer:

Step-by-step explanation:

Suppose x/b+c=y/c+a=z/a+b=k

x=k(b+c), y=k(c+a), z=k(a+b)

(b-c)x=k(b-c)(b+c)=k(b^2-c^2) 1st equation

Similarly (c-a)y=k(c^2-a^2) 2nd equation

(a-b)z= k(a^2-b^2) 3rd equation

Add 1st, 2nd and 3rd equations

(b-c)x+(c-a)y+(a-b)z=k(b^2-c^2+c^2-a^2+a^2-b^2)

(b-c)x+(c-a)y+(a-b)z=0 proved

I hope this is the answer.

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