Question

(x^b/x^c)b+c-a(x^c/x^a)c+a-b(x^a/x^b)a+b-c​

Answer 1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

there has a mistake in the sum

the real sum is

(x^b/x^c)^(b+c-a) × (x^c/x^a)^(c+a-b) × (x^a/x^b)^(a+b-c)

= x^[(b-c)(b+c-a)]×x^[(c-a)(c+a-b)]×x^[(a-b)(a+b-c)]

= x^(b²-c²-ab+ac)×x^(c²-a²-bc+ab)×x^(a²-b²-ac+bc)

= x^(b²-c²-ab+ac+c²-a²-bc+ab+a²-b²-ac+bc)

= x^0

= 1

I hope that it is helpful