x^b•y = 2x - 3y² , find (1/2)^b • 1√3
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Eq1[/math] X+3Y=1 Divide by 6 X/6+Y/2=1/6 X /6=1/6-Y/2 ……eq2 Put eq2 in eq1 ... Putting this in the first equation we get:(1/6)-(y/2)-(1/y )=2. ... 《(x,y)=(-8,3),(-1,2/3)》(1 ...
The solutions are: x = 3 , y = -2/3 x = 10 , y = -3
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