x^b2 . x^b2-2ab . x^a2-b2
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Answer:
(a−b)x+(a+b)y=a
2
−2ab−b
2
----- (i)
(a+b)(x+y)=a
2
+b
2
-------- (ii)
Subtracting eq (i) by eq (ii), we get.
⇒(a−b)x−(a+b)x=a
2
−2ab−b
2
−a
2
−b
2
⇒−2bx=−2bx(a+b)
⇒x=(a+b)
∴(a+b)(a+b+y)=a
2
+b
2
⇒(a+b)
2
+(a+b)y=a
2
+b
2
⇒y=
a+b
−2ab
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