Question

x= -c/ab then bx²+ ax-ab​

Answer 1

Answer:

x= -c/ab then bx²+ ax-ab answer is 3

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Answer 2

Answer:

If,

x=(-c/ab)

Then,

bx²+ax-ab

=b(-c/ab)²+a(-c/ab)-ab

=b(c²/a²b²)+a(-c/ab)-ab

=(c²/a²b)-(c/b)-ab

=[c²-c(a²)-ab(a²b)]/(a²b)

=(c²-a²c-a³b²)/(a²b)