Math, asked by DasanPilla239, 1 year ago

X can complete a job in 30 days. y can complete the job in 60 days. both work together along with z to complete job in 10 days . fine the share of z in a total of 6000 paid for work

Answers

Answered by auzu052
6

Answer:

X can complete a job in 30 days. y can complete the job in 60 days. both work together along with z to complete job in 10 days . fine the share of z in a total of 6000 paid for work

Answered by Hansika4871
0

Given:

X can complete a job in 30 days, Y can complete the same job in 60 days. Both X and Y along with Z complete the work in 10 days together. An amount of 6000 is paid for completing the project to all of them.

To Find:

The share Z has received in completing the work.

Solution:

1. It is given that X can complete a job in 30 days,

=> Work done by X every day = (1/30).

2. For the same job Y takes 60 days,

=> Work done by Y in 1 day = (1/30),

3. Let the work done by Z per day be denoted as z.

4. For 10 days,

  • Work done by X = 10 x (1/30) = 1/3,
  • Work done by Y = 10 x ( 1/60) = 1/6,
  • Work done by Z = 10 x z = 10z.

5. Work done by X, Y, and  Z together for 10 days completes the job. Hence,

=>\frac{1}{3} +\frac{1}{6} +10z=1,

=> 10z = 1 - (1/2),

=> 10z = 1/2,

=> z= (1/20).

6. The fractions of work done by X, Y, and Z for 10 days are (1/3), (1/6), (1/2). The payment received by Z will be,

=> Share of Z in the project = (fraction of work) x 6000,

=> Share of Z = 0.5 x 6000,

=> Share of Z = 3000.

Therefore, the share of z in a total of 6000 is 3000.

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