Question

X can complete a task in 15 days and Y can complete the same task in 20 days. X started the task alone and after 5 days Y joins X. After working together for three
days, X had to leave the work. How long does it take for Y to complete the remaining work?
OOOO
4.5 days
5.3 days
2.5 days
O 6.3 days​

Answer 1

Answer:

hlo dear ♥️

Step-by-step explanation:

• Let the total work is 60 units. X can complete the work 15 days, so he can do 4 units in one day. Similarly Y can do 3 units in one day. Now in the first 5 days, X will do 5 × 4 = 20 units and in next three days x and Y will work 7 × 3 = 21 units.
• The total work done till now is 20 + 21 = 41 units. The remaining work is 19 units, which will be done by Y alone and he will take 19/3 = 6.3 days .

Answer 2

Answer:

BRAINLIST

Step-by-step explanation:

assume the work done to be 60 units which is the lcm of 20 and 12

so X completes the work in 20 days that means he does 3 units of work in one day(60/20=3)

and similarly Y completes the work in 12 days that means he does 5 units of work in one day(60/12=5)

now X starts the work and works alone for 4 days that means he completes 4*3=12 units of work in 4 days

now the remaining work is 60–12=48

now Y joins X so total units that can be completed in 1 day =3+5=8

now the remaining work can be completed by X and Y in 6 days that is 48/8=6

so total days required to complete the work is 4+6=10 days

so your answer will be 10 days

hope it helps

PLEASE MARK AS BRAINLIST