Question

x can do a piece of work in 12 days and y can do the work in 20 days . They work together for 3 days and then x goes away. In how many days y finish the work​

Answer 1

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Let the required days be x.

A works for (x - 2) days, while B works for x days.

According to the question,

x−210+x20=1

2x- 4 + x = 20

3x = 24

x = 8 days

hope it helps....

Answer 2

Step-by-step explanation:

X does the work in 20 days

=>In 1 day X will do 1/20 part of the work

=>In 3 days X will do 3/20 part of the work

Y does the work in 12 days

=>In 1 day Y will do 1/12 part of the work

=>In 3 days Y will do 3/12 i.e. 1/4 part of the work

Total work done after 3 days is :

$\frac{1}{4} + \frac{3}{20} \\ = \frac{8}{20 } \\ = \frac{2}{5} parts \: of \: total \: work$

Remained work is

$1 - \frac{2}{5} \\ = \frac{3}{5} parts \: of \: total \: work$

So Y will take

$\frac{ \frac{3}{5} }{ \frac{1}{4 } } \\ = \frac{3}{5} \times \frac{4}{1} \\ = \frac{12}{5} = 2 \frac{2}{5} days$

So total time = 3+2.4 = 5.4 days or 5 days 10hrs

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