Math, asked by pankajshukla5, 1 year ago

X can do a piece of work in 14 hours and Y can do a piece of work in 24 hours excludes the work 2 hours before the completion of the work how long does they work together

Answers

Answered by vickyrajputana78
0

Let the Whole work be ‘1″

A takes 15 days to complete the whole work, hence A completes 1/15th of the work in 1 day.

B takes 20 days to complete the whole work, hence B completes 1/20th of the work in 1 day.

In one day A and B can together complete 1/15th+1/20th of the work, adding it up will make 7/60.

A’s work for 6 days will be 6*1/15=6/15. Similarly B’s work for 6 days will be 6/20

For 6 days the work will be 6/15+6/20=42/60.

Now, the remaining work is completed by C, Remaining work will be “Whole work less work completed by A and B together.”

That will be equal to 1–42/60, simplifying it further C has done here 18/60 of the work.

Now, Ratio between A, B and C’s work here will be 6/15:6/20:18/60, Make the denominators equal to 60. A’s work is 6/15*4/4=24/60. B’s work is 6/20*3/3=18/60.

Ratio between A, B and C will be = 24/60:18/60:18/60.

Now, A’s share of 6,500 = 6,500*24/60=2600

Similarly B’s Share = 6,500*18/60 = 1850

Similarly C’s Share = 6,500*18/60 = 1850

Similar questions