Math, asked by rakeshsri444, 18 days ago

X can do a piece of work in 20 days and Y can do the 1/7th of the same work in 5 days. In how many days together they can complete the 11/14th of the total work?​

Answers

Answered by vaishnaviy191206
3

Answer:

Answer is 10 days

Step-by-step explanation:

y can do in 1 day = 1/(7x5) = 1/35 x & y can do in 1 day= 1/20+1/35-11/140

Now,

11/140 work is done in 1 day So, 1 work is done in 140/11 day So, 11/14 work is done in (140x11)/(11x14) = 10 days

hope it's help you

Answered by igpprisons
0

Answer:

10 days is the answer

Step-by-step explanation:

Y can do in 1 day = 1 / (7×5)=1/35

X and Y can do in 1 day = 1 /20 + 1/ 35 =11/ 140

now :

11/ 140 work os done by 1 day

so, 1 work is done by 140/ 11 day

so,11/ 140 work is done in

( 140 × 11 ) / (11 × 14 ) = 10 days

Similar questions