Question

X can do a work in 30 days and Y can do a work in 25 days. They worked together for 10 days and then X left. In how many days will Y finish the remaining work? (Find answer in decimals) *

Answer 1

$\huge\bold{\underline{Question:}}$

X can do a work in 30 days and Y can do a work in 25 days. They worked together for 10 days and then X left. In how many days will Y finish the remaining work? (Find answer in decimals) *

$\huge\bold{\underline{Answer:}}$

GIVEN:

• X can do a work in 30 days and Y can do a work in 25 days

• They worked together for 10 days and then X left.

TO FIND:

In how many days will Y finish the remaining work?

SOLUTION:

Let the total work be 1

Then, According to question X takes 30 days to do 1 work.

Then, work done by X in 1 day = 1/30

Also according to question Y takes 25 days to do 1 work

Then ,work doe by Y in 1 day = 1/25

Then total work done by both of them in 1 day

$\sf{\implies \dfrac{1}{30}+\dfrac{1}{25}}$

$\sf{\implies \dfrac{11}{150}}$

Then total work done by both of them 10 days =$\bf{\dfrac{110}{150}}$

Total work left = $\bf{1-\dfrac{110}{150}}$

Total work left = $\bf{\dfrac{40}{150}}$

Now, this remaining work is done by B.

Let Y takes ' a ' days to complete it.

$\sf{\implies \dfrac{1}{25} × a =\dfrac{40}{150}}$

$\sf{\implies a =\dfrac{40}{150}× 25}$

$\boxed{\bf{\pink{a=6\dfrac{2}{3}\:days}}}$

Hence, Y will finish the remaining work in $\boxed{\bf{\pink{=6\dfrac{2}{3}\:days}}}$

Answer 2

Answer:

☃️Question:-

X can do a work in 30 days and Y can do a work in 25 days. They worked together for 10 days and then X left. In how many days will Y finish the remaining work? (Find answer in decimals) *

☃️Answer:-

GIVEN:

X can do a work in 30 days and Y can do a work in 25 days

They worked together for 10 days and then X left.

TO FIND:

In how many days will Y finish the remaining work?

SOLUTION:

Let the total work be 1

Then, According to question X takes 30 days to do 1 work.

Then, work done by X in 1 day = 1/30

Also according to question Y takes 25 days to do 1 work

Then ,work doe by Y in 1 day = 1/25

Then total work done by both of them in 1 day

$: \implies \: \frac{1}{30} + \frac{1}{25} \\ : \implies \: \frac{11}{150}$

$Then \: total \: work \: done \: by \: both \: of \: them \: 10 days =\bf{\dfrac{110}{150}}$

$Total \: work \: left = \bf{1-\dfrac{110}{150}}1−$

$Total \: work \: left = \bf{\dfrac{40}{150}}$

Now, this remaining work is done by B.

Let Y takes ' a ' days to complete it.

$\frac{1}{25} \times a = \frac{40}{150}$

$a = \frac{40}{125} \times 25$

$a = 6 \frac{2}{3} \: days$