Question

X can do a work in 60 days. y is 33.33% more efficient than x. how long does y take to complete the work?

Answer 1

time taken by x to do work=60 days ATQ 33.33% of 60 + 60=time y would take 33.33/100 +60 (33.33+6000)/100 6033.33/100 60.3333 days y would take.     I hope I would help u  Thankss

Answer 2

So, going with the problem , X can do the job in 60 days but Y is 33.33% more efficient , that means that B can do it in less days.....how much ? let's find out...

Now

Since Y 's efficiency is relative to X , consider Y 's nos. of days to be "a"

Let 1 day work of Y  = 1/a  ,

∴ 1 day work of X = 1/60

So, ATP

The efficiency of B is =

[ { (1/a)-(1/60) }/ (1/60) ] * 100 = 33.33 (Since Y  is 33.33% more efficient than A)

⇒ [  (60-a) / a ] * 100 = 33.33

⇒  (60-a) / a  = 33.33 / 100

⇒   (60-a) /a =0.3333

⇒ 60-a =0.3333a

⇒ 60 =[0.3333a +a]

⇒ 1.3333a = 60

⇒ a = 60 / 1.3333 days   = 45.days ANS