Question

x can do piece of work in 12 days,y can piece of work 15 days,z can do in 20 days,if one of the first day x worked alone on the second day x nd y tigether and thurd day x and y and z worked together,if they repeat the cycle,then how many days total work can be compl
ted..??
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Answer 1

Answer:

the selling price is less than the cost price there is a ________

Answer 2

days work per day

x 12 1/12

y 15 1/15

z 20 1/20

work done by x + (x+y) + (x+y+z)

= 1/12 +(1/12 +1/15) + (1/12 + 1/15 +1/20)

= 26/60

there are 2 26s in 60

=> 2×3 = 6 days taken

remaining work = 1 -(2× 26/60) = 2/15

x does work next day

remaining = 2/15 - 1/12 = 1/20

x+y =1/12 + 1/15 = 3/20

no of days x+y takes to finish 1/20 part of work is

1/20 ÷ 3/20 =1 ÷3 =1/3 days

total no. of days = 2×3 =6 + 1+⅓ = 7⅓ days

to finish the work