x can finish 2/3 of a work in 6 days and y can finish 3/4 of the same work in 9 days. they worked together for 2 days and then y left. the remaining work was done by x. how much time did x take to finish the remaining work?
Answers
Answered by
0
Step-by-step explanation:
x can finish 2/3 of work in 6 days
x can finish 1 whole work in 6÷2/3= 6×3/2
= 9 days
x can finish 1/9 of work in day
y can finish 3/4 of work in 9 days
y can finish 1 whole work in 9-3/4 =9x4/3= 12 days
y can finish 1/12 part of work in 1 day
work done by X and y in 1 day
= 1/9 + 1/12 = 4+3/36 = 7/36
work done by x and y in 2 days = 2× 7/36
= 7/18
remaining work = 1-7/18 - 11/18
x oes 1/9 part of work in 1 day
dos 11/18 part of work in 9×11/18 - 11/2 =5 1/2 days
x does remaining part of work in 5 1/2 days
please follow me and mark me as brainliest
Similar questions