X coordinate of the particle moves along xaxis is given by x=16t-2t^2, where t is in time . find the distance travelled by the particle from t=0 to t=8 sec.
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To find The distance travelled from time t=0 to t=8sec
first we will need to find velocity.
that is dx/dt
dx/dt =16-4t
by this you can see the velocity will become 0 at t=4 sec and after 4 sec it will be negative.
We need distance so we will make it positive.
so distance travelled in 8 sec=2×distance travelled in 4sec.
x=2(16t-2t^2) at t=4sec
x=2(64-32)
x=64
first we will need to find velocity.
that is dx/dt
dx/dt =16-4t
by this you can see the velocity will become 0 at t=4 sec and after 4 sec it will be negative.
We need distance so we will make it positive.
so distance travelled in 8 sec=2×distance travelled in 4sec.
x=2(16t-2t^2) at t=4sec
x=2(64-32)
x=64
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