Question

x = cos θ – cos 2θ, y = sin θ – sin 2θ find dy/dx

Answer 1

dy/dx = (Cosθ  - 2Cos2θ)/(2Sin2θ - Sinθ) , x = cos θ – cos 2θ, y = sin θ – sin 2θ

Step-by-step explanation:

dy/dx

x = cos θ – cos 2θ

y = sin θ – sin 2θ

x = cos θ – cos 2θ

dx/dθ  = -Sinθ  -  (-2Sin2θ)

=> dx/dθ  = 2Sin2θ - Sinθ

y = sin θ – sin 2θ

dy/dθ  = Cosθ  - 2Cos2θ

(dy/dθ)/(dx/dθ)  =  (Cosθ  - 2Cos2θ)/(2Sin2θ - Sinθ)

=> dy/dx = (Cosθ  - 2Cos2θ)/(2Sin2θ - Sinθ)

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