X could complete a piece of work in 16 hours and Y could complete the same work in 20 hours.They worked together for 8 hours and then Y left.Find the time required by X to complete the remaining work alone.
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X can do a piece of work in 25 days and Y can finish it in 20 days. They work together for 5 days and then X leaves. In how many days will Y finish the remaining work ?
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ANSWER
Let the total work be 1
Then, According to question X takes 25 days to do 1 work.
Then work done by X in 1 day=
25
1
Also according to question Y takes 20 days to do 1 work.
Then work doe by Y in 1 day=
20
1
Then total work done by both of them in 1 day =
20
1
+
25
1
=
100
9
Then total work done by both of them 5 days=
100
45
Then total work left =1−
100
45
=
100
55
Now, As Y can do 1 work in 25 days therefore,
Y can do
100
55
work in
100
55
×25 days
=
4
55
days
Answered By mark as brainiest