Question

x cube + 13 x square + 32 X + 20 ​

Answer 1

Answer:

Hey mate, please mention full question.

I am factorising it .

x³ + 13x² +32x +20

So, first of all , by hit and trial method

(x+1) is a factor .

so, divide x³ + 13x² + 32x + 20 by x+1

on dividing ,we get x² + 12x + 20

now,

x² + 12x + 20

= x² + 10x + 2x + 20

= x(x+10) + 2(x+10)

= (x+2) (x+10)

(x+1) , (x+2) , (x+10) are the factors of the given polynomial.

if we have to find the zeroes ofbthe polynomial

then,

-1 , -2 , -10 are the zeroes of the given polynomial.

Hope it helps you!!!

please mark it as brainliest...

Answer 2

Question

x³ + 13x² + 32x + 20

Let's solve it

▶️ x³ + 13x² + 32x + 20

▶️ x³ + x² + 12x² + 12x + 20x + 20

▶ x²(x + 1) + 12x(x + 1) + 20(x + 1)

️▶ (x + 1) (x² + 12x + 20)

️▶ ️(x + 1) (x² + 2x + 10 + 20)

▶ (x + 1) (x(x + 2) + 10(x + 2))

️▶ (x + 1) (x + 2) (x + 10)

$\:$

So, factors are :- (x + 1) (x + 2) (x + 10)