Question

x cube+13xsquare+32x+20

Answer 1

Factorization,

We have,

x³ + 13x² + 32x + 20

Theres a trick to solve such question.
verify the expression by replacing x with any sutable number that gives the result of the expression as 0

In this case if we replace the value of x by -1 then the value of the expression becomes 0

and one of the factors of the expression would be (x - @) where @ is the number that suits the expression by replacing x, in this case -1.

So we found one factor,
Lets find another,

x³ + x² + 12x² + 12x + 20x + 20 [you have to cunningly make a factor (x + 1),in other questions it may not be (x + 1), it could be (x - 1) or (x + 2),it depends on you ]

= x²(x + 1) + 12x(x + 1) + 20(x+ 1)

= (x + 1)(x² + 12x + 20)

= (x + 1)(x² + 10x + 2x + 20)

= (x + 1){x(x + 10) + 2(x + 10)}

= (x + 1)(x + 10)(x + 2)

= (x + 1)(x + 2)(x + 10)

Thats it
Hope it helped ヾ(｡>﹏<｡)ﾉﾞ✧*。