x cube+23xsquare+142x-240 factorize it. plz do it fast
Answers
Answered by
1
Hey,
Correction in the question:-
x3- 23x2+142x-120
let p(x)= x3- 23x2+142x-120
g(x)=x-1
0=x-1
x=1
p(1)=(1)3-23(1)2+142(1)-120
=1-23+142-120
=143-143
=0
Hence x-1 is a factor of x3- 23x2+142x-120
by long division
x3- 23x2+142x-120 = (x-1)(x2+22x+120)
=(x-1)(x2+10x+12x+120)
=(x-1)(x(x+10) 12(x+10))
=(x-1)(x+12)(x+10)
HOPE IT HELPS YOU:-))
Correction in the question:-
x3- 23x2+142x-120
let p(x)= x3- 23x2+142x-120
g(x)=x-1
0=x-1
x=1
p(1)=(1)3-23(1)2+142(1)-120
=1-23+142-120
=143-143
=0
Hence x-1 is a factor of x3- 23x2+142x-120
by long division
x3- 23x2+142x-120 = (x-1)(x2+22x+120)
=(x-1)(x2+10x+12x+120)
=(x-1)(x(x+10) 12(x+10))
=(x-1)(x+12)(x+10)
HOPE IT HELPS YOU:-))
Similar questions