Question

x cube-2x sqare -x+2​

Answer 1

Answer:

x=1, x=2, x= -1

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Step-by-step explanation:

Let f(x)=x³-2x²-x+2

if we put x=1 in the equation we get 0

so (x-1) is a factor of x³-2x²-x+2 .That means if we divide the equation by (x-1) we get remainder zero.

now dividing,

x-1 ) x³-2x²-x+2 ( x²-x-2

-( x³- x²)

-x²-x

-(-x²+x)

-2x+2

-(-2x+2)

0

Thus f(x)=(x-1)(x²-x-2)

=(x-1)(x²+x-2x-2)

=(x-1)(x+1)(x-2)

Therefore, for x=1, x= -1 and x=2

we get f(x) equal 0