x cube _2x square _x+2
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Answered by
3
x³ - 2x² - x + 2
=> x²(x - 2) - 1(x - 2)
=> (x - 2)(x² - 1)
=> (x - 2){(x)² - (1)²}
=> (x - 2)(x - 1)(x + 1)
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Answered by
0
Step-by-step explanation:
x³-2x²-x+2
= x³-x²-x²+x-2x+2
= x²(x-1) -x(x-1)-2(x-1)
=(x-1) (x²-x-2)
= (x-1) [ x²-2x+x-2]
= (x-1) [ x( x-2) +1(x-2)]
= (x-1)(x-2)(x+1)
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