Question

x cube + 3 x square minus x minus 3 find one by Alpha Plus One by beta Plus plus one by gama​

Answer 1

Answer:

${x}^{3} + 3 {x}^{2} - x + 3 \\ a = 1 \: \: b = 3 \: \: \: \: c = - 1 \: \: \: d = 3 \\ = \frac{1}{ \alpha } + \frac{1}{ \beta } + \frac{1}{ \gamma } \\ = \frac{ \beta \gamma + \alpha \gamma + \alpha \beta }{ \alpha \beta \gamma } \\ = \frac{ \frac{c}{a} }{ \frac{d}{a} } \\ = \frac{c}{a} \times \frac{a}{d} \\ = \frac{c}{d} \\ = \frac{ - 1}{3}$