X cube+3x cube +3x+1 factorise using suitable identities
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Here's ur answer
x³+3x²+3x+1
= (x)³ + 3*(1)*(x)² + 3*(1)²*x + (1)³
This is of the form
(a+b)³ = a³+b³+3a²b+3ab²
Hence,
x³+3x²+3x+1
= (x+1)³
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