x cube - 3x square + 3x - 7
factorize
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Answer:
x³ - 3x² + 3x + 7
= x³ - 3x² + 3x - 1 + 8
= {x³ - 3x² + 3x - 1} + (2)³
= {x³ - 1 - 3x²+ 3x} + (2)³
= {(x)³ - (1)³ - 3(x)² × 1 + 3 × x × (1)²} + (2)³[a³- b³ - 3a²b + 3ab² = (a-b)³]
= (x - 1)³ + (2)³
= (x - 1 + 2){(x - 1)² - (x - 1)•(2) + (2)²}
= (x + 1)(x² - 2x + 1 - 2x + 2 + 4)
= (x + 1)(x² - 4x + 7)
ps. please mark as brainliest answer. Takes effort n time and it only counts for 5 PTS.
Thank you✨
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