Question

(x cube - 3x square - x ) ( x square - 3x + 1 )
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Answer 1

$( {x}^{3} - 3 {x}^{2} - x)( {x}^{2} - 3x + 1) \\ = {x}^{5} - 3 {x}^{4} + {x}^{3} - 3 {x}^{4} + 3 {x}^{3} - 3 {x}^{2} - {x}^{3} + 3 {x}^{2} - x \\ = {x}^{5} - 6 {x}^{4} + 3 {x}^{3} - x$

HOPE THIS COULD HELP!!!