Question

X cube + 4 x square + 3 x minus 4 and x cube minus 4 x a divided by x minus 3 by remainder theorem

Answer 1

$by \: remainder \: theorem \\ x = - 3 = 0 \\ x = 3 \\ {x}^{3} + 4 {x}^{2} + 3x - 4 \\ = {3}^{3} + 4( {3}^{2} ) + 3(3) - 4 \\ = 27 + 36 + 9 - 4 \\ = 68$