Question

X cube + 4 x square + 9 x + 2 divided / x + 1

Answer 1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

$={x}^{3} + {4x}^{2} + 9x + 2$

$let \: it \: be \: p(x)$

$p(x) \: is \: divided \: by \: x + 1$

$x + 1 = 0$

$then \: x = - 1$

$p(x) = {x}^{3} + {4x}^{2} + 9x + 2$

$p( - 1) = { - 1}^{3} + 4 {( - 1)}^{2} + 9( - 1) + 2$

$\: \: \: \: \: \: \: \: \: \: \: \: \: = - 1 + 4 - 9 + 2$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 6 - 10$

$\: \: \: \: \: \: \: \: \: \: \: = - 4$

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