Math, asked by 16vs1010384, 1 month ago

x cube-6x square+11x-6

Answers

Answered by UnknownWe2006
1

 {x}^{3}  - 6 {x}^{2}  + 11x - 6 \\  \\  {x}^{3}  - 5 {x}^{2}  -  {x}^{2}  + 5x + 6x - 6 \\  \\   {x}^{3}   -  5 {x}^{2}  + 6x -  {x}^{2}  + 5x -6 \\  \\ x( {x}^{2}  - 5x + 6) - 1( {x}^{2}  - 5x + 6) \\  \\ ( {x}^{2}  - 5x + 6)(x - 1) \\  \\ ( {x}^{2}  - 2x   -  3x + 6)(x - 1) \\  \\ (x(x - 2) - 3(x - 2))(x - 1) \\  \\ (x - 3)(x - 2)(x - 1) \: answer

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