Question

x cube - 6x square +9x+3 is divided by x-1

Answer 1

X³-6X²+9X+3 is divided by X-1

We get,

Quotient = X²-5X+4

and

Remainder = 7

FACTORIES THE QUOTIENT X²-5X+4

Then,

We get the zeros of the polynomial X²-5X+4

X²-5X+4

X²-4X-X +4

X(X-4) + 1 ( X-4)

(X-4) ( X+1)

X-4 = 0. X+1 = 0

X = 4. X = -1

Answer 2

hope this is help ful to you