x cube + 8 y cube minus 2 (X + 2 y)
Answers
Answer:
The value of polynomial x^3-8y^3-36xy-216x
3
−8y
3
−36xy−216 when x = 2y + 6 is 0.
Step-by-step explanation:
Given: polynomial x^3-8y^3-36xy-216x
3
−8y
3
−36xy−216
We have to find the value of polynomial when x = 2y + 6
Consider the given polynomial x^3-8y^3-36xy-216x
3
−8y
3
−36xy−216
Substitute x = 2y + 6, we get,
(2y+6)^3-8y^3-36(2y+6)y-216(2y+6)
3
−8y
3
−36(2y+6)y−216
Simplify, we get,
Using algebraic identity (a+b)^3=a^3+b^3+3a^2b+3ab^2(a+b)
3
=a
3
+b
3
+3a
2
b+3ab
2
(2y)^3+6^3+72y^2+216y-8y^3-36(2y^2+6y)-216(2y)
3
+6
3
+72y
2
+216y−8y
3
−36(2y
2
+6y)−216
Simplify further , we get,
216+72y^2+216y-72y^2-216y-216216+72y
2
+216y−72y
2
−216y−216
Simplify, we get
216+72y^2+216y-72y^2-216y-216=0216+72y
2
+216y−72y
2
−216y−216=0
Hence, the value of polynomial x^3-8y^3-36xy-216x
3
−8y
3
−36xy−216 when x = 2y + 6 is 0.
Answer:
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