Question

x cube -8y cube (find factor using formula)

Answer 1

$x {}^{3} - 8y {}^{3}$

So apply identity

$(x {}^{3} - y {}^{3} ) = (x - y)(x {}^{2} + y {}^{2} + xy)$

$(x - 2y)(x {}^{2} + y {}^{2} + 4xy)$

Thanks

Answer 2

(a^3 - b^3 )= (a-b)(a^2 +ab +b^2 )
(X^3 - (2y)^3) = (x-2y)(x^2 +2xy + 4y^2)