x cube divided by 8 + y cube divided by 27
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Hi ,
x³ / 8 + y³ /27
= ( x/2 )³ + ( y/3 )³
= ( x/2 + y/3 )[ ( x/2 )²-(x/2)(y/3)+(y/3)² ]
= ( x/2 + y/3 ) [ x²/4 - xy/6 + y²/9 ]
I hope this helps you.
:)
x³ / 8 + y³ /27
= ( x/2 )³ + ( y/3 )³
= ( x/2 + y/3 )[ ( x/2 )²-(x/2)(y/3)+(y/3)² ]
= ( x/2 + y/3 ) [ x²/4 - xy/6 + y²/9 ]
I hope this helps you.
:)
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