x cube minus 2 x square - 5 x + 6
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Given x^3 - 2x^2 - 5x + 6 can be written as
= (x - 1)(x^2 - x - 6)
= (x - 1)(x^2 + 2x - 3x - 6)
= (x - 1)(x(x+2) - 3(x+2))
= (x - 1)(x + 2)(x - 3).
Hope this helps!
= (x - 1)(x^2 - x - 6)
= (x - 1)(x^2 + 2x - 3x - 6)
= (x - 1)(x(x+2) - 3(x+2))
= (x - 1)(x + 2)(x - 3).
Hope this helps!
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