Question

x cube minus 2x square minus x + 2​

Answer 1

Answer:

(x-2)(x-1)(x+1)

Step-by-step explanation:

try photomath app from google play store

Answer 2

Question:

x³ - 2x² - x + 2

Solve by factorization method and find it's zeros.

Solution:

x³ - 2x² - x + 2

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• We have to find it's zeros.

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We know that ax² + bx + c = 0

→ x³ - 2x² - x + 2 = 0

Take x² common from (x³ - 2x²) and (-1) from (- x + 2)

→ x²(x - 2) -1(x - 2) = 0

→ (x² - 1) (x - 2) (x - 2) = 0

→ (x - 1) (x + 1) (x - 2) = 0

If we have to solve it by factorization then answer is $\underline{\bold{(x \:- \:1) \:(x \:+ \:1) \:(x \:- \:2)}}$

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*But if we have to find zeros then further processor are as follows:

Now.. put them equal to 0. One by one

» x² - 1 = 0

→ x² = 1

→ x = ±1

» x - 2 = 0

→ x = + 2

» x - 2 = 0

→ x = +2

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±1, +2, +2 are the zeros of x³ - 2x² - x + 2.

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