Question

x cube minus 3 X square + 5 x minus 3 divided by xsquar-2

Answer 1

your answer in picture

Answer 2

Answer:

$Dividend = x^3-3x^2+5x-3$

$Divisor =x^2-2$

Since we know that

$Dividend = (Divisor \times Quotient )+Remainder$

$x^3-3x^2+5x-3 = (x^2-2 \times x )+(-3x^2+7x-3)$

$x^3-3x^2+5x-3 = (x^2-2 \times x-3 )+(7x-9))$

So, the quotient is (x-3)and the remainder is (7x-9) .