Math, asked by anjut6993, 10 months ago

x cube minus 3 x square - 8 x + 3 by x square - 4 x + 3 divide the reminder will be​

Answers

Answered by radhikap1984
1

Answer:

x^3 - 3x^2- 8x +3/ x^2 - 4x +3

Step-by-step explanation:

now lets take x^3 - 3x^2- 8x +3 as equation 1

and x^2 - 4x +3 as equation 2

now factorise equation 2 as we cannot factorise eq 1

x^2 - 4x +3 = x^2 - 3x - x +3

= x(x - 3) -1(x - 3)

=(x - 1)(x - 3)

now the question is x^3 - 3x^2- 8x +3/(x - 1)(x - 3)

i guess x^3 - 3x^2- 8x +3 this equation is wrong

Answered by venkatavineela3
0

Answer:

Step-by-step explanation:

x^2-4x+3)x^3-3x^2-8x+3(x+1

              x^3-4x^2

=------------------------------------------

                  x^2-8x+3

                 x^2-4x+3

--------------------------------------

-4x

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