x cube minus 3 x square - 8 x + 3 by x square - 4 x + 3 divide the reminder will be
Answers
Answered by
1
Answer:
x^3 - 3x^2- 8x +3/ x^2 - 4x +3
Step-by-step explanation:
now lets take x^3 - 3x^2- 8x +3 as equation 1
and x^2 - 4x +3 as equation 2
now factorise equation 2 as we cannot factorise eq 1
x^2 - 4x +3 = x^2 - 3x - x +3
= x(x - 3) -1(x - 3)
=(x - 1)(x - 3)
now the question is x^3 - 3x^2- 8x +3/(x - 1)(x - 3)
i guess x^3 - 3x^2- 8x +3 this equation is wrong
Answered by
0
Answer:
Step-by-step explanation:
x^2-4x+3)x^3-3x^2-8x+3(x+1
x^3-4x^2
=------------------------------------------
x^2-8x+3
x^2-4x+3
--------------------------------------
-4x
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