x cube minus 6 X square + 11 x + 6 factorise
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Given (x^3)-6(x^2)+11x-6=0
let x=1 is the factor of the equation
1 |1 -6 11 -6
| 0 1 -5 6
-----------------------
1 -5 6 0
hence x=1 is one of the factor
=>x^2-5x+6=0
=>x^2-2x-3x+6=0
=>x(x-2)-3(x-2)=0
=>(x-2)(x-3)=0
hence factor are (x-1)(x-2)(x-3)=0
@skb
let x=1 is the factor of the equation
1 |1 -6 11 -6
| 0 1 -5 6
-----------------------
1 -5 6 0
hence x=1 is one of the factor
=>x^2-5x+6=0
=>x^2-2x-3x+6=0
=>x(x-2)-3(x-2)=0
=>(x-2)(x-3)=0
hence factor are (x-1)(x-2)(x-3)=0
@skb
ydbvfnsiebd:
thanks you helped me a lot
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4
Hey my friend ,
The Q you mentioned above is wrong because according to Subject Math/algebra we can factorise those equations which are quadratic means the biggest index must be 2.....of the equation.
HOPE I MUST HELP YOU.
The Q you mentioned above is wrong because according to Subject Math/algebra we can factorise those equations which are quadratic means the biggest index must be 2.....of the equation.
HOPE I MUST HELP YOU.
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