Question

x cube minus 6 X square + 9 X + 3 is divided by x minus 1 using remainder theorem find remainder

Answer 1

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Answer 2

By remainder theorem:

x-1=0

x= 1

x^3-6x^2+9x+3

=(1)^3 - 6(1)^2 + 9(1) + 3

= 1-6+9+3

=7