x cube + x square minus 2
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Answer :
Now,
x³ + x² - 2
= x³ + x² - 1 - 1
= x³ - 1 + x² - 1
= (x³ - 1) + (x² - 1)
= (x - 1)(x² + x + 1) + (x + 1)(x - 1)
= (x - 1)(x² + x + 1 + x + 1)
= (x - 1)(x² + 2x + 2),
which is the required factorization.
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Now,
x³ + x² - 2
= x³ + x² - 1 - 1
= x³ - 1 + x² - 1
= (x³ - 1) + (x² - 1)
= (x - 1)(x² + x + 1) + (x + 1)(x - 1)
= (x - 1)(x² + x + 1 + x + 1)
= (x - 1)(x² + 2x + 2),
which is the required factorization.
#MarkAsBrainliest
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