Question

x cube - y cube if x-y=2​

Answer 1

Answer:

x-y=2,xy=3. so x+y = root over of (x-y)²+4xy. = root over of 2²+3×4. =root over of 16. =4. x+y=4. then. x³-y³=(x-y)(x²+xy+y²).

Answer 2

Answer:

${x}^{3} - {y}^{3} \\ {(x - y)}^{2} + 3xy(x - y) \\ {2}^{2} + 3xy(2) \\ 4 + 6xy$