X cube+Y cube if X+Y =3 and XY = 2
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Xcube+Ycube
=(X+Y) ^3 - 3(X+Y)(XY)
Putting the values of X and Y
=(3)^3 -3(3)(2)
=27 - 18
=9
=(X+Y) ^3 - 3(X+Y)(XY)
Putting the values of X and Y
=(3)^3 -3(3)(2)
=27 - 18
=9
tony19:
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