Question

X cube - y cube = (x-y) (xsquare-xy+y square
If x=3, Y=2

Answer 1

Step-by-step explanation:

THE EQUATION IS WRONG IT IS $x^{3} -y^{3} = (x-y)(x^{2} + xy +y^{2} )$

The left hand side of the equation will become $3^{3} - 2^{3}= 27 - 8 = 19$

The right hand side of the equation will become $(3-2)*(3^{2} + 2*3+2^{2})=1*(9+6+4)=1*19=19$