Question

x cube+y cube+ z cube minus 3 xyz
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Answer 1

Answer:

x3 + y3 +z3 - 3xyz = (x+y+z)(x2 + y2 + z2 - xy - yz - zx)

Answer 2

${\huge{\boxed{\boxed{\mathfrak{\purple{Answer:-}}}}}}$

${x}^{3} + {y}^{3} + {z}^{3} - 3xyz \\ = > (x + y + z)( {x}^{2} + {y}^{2} + {z}^{2} - xy - yz - zx)$