Question

x does one job in 12 days, x and y do the same job together in 8 days, how many days will y alone complete the job? *
please send ans​

Answer 1

Answer:

may be they may complete the work in 24 days

Answer 2

Step-by-step explanation:

Given:-

Time taken by x to finish the job = 12 days

Time taken by (x + y) to finish the job = 8 days

To find:-

Time taken by y to finish the job

Solution:-

$(x \: + \: y) \: days \: to \: finish \: the \: work \: = \: \frac{1}{8} days$

$x \: days \: to \: finish \: the \: work \: = \: \frac{1}{12} days$

$\frac{1}{8} - \: \frac{1}{12}$

Let's take the L.C.M of 8 and 12 = 24

$\frac{1}{8} \times \: 4 \:$

and

$\frac{1}{12} \times \: 2$

$= \: \frac{4}{24} - \: \frac{2}{24}$

$= \: \frac{2}{24}$

$= \: \frac{1}{12}$

Hence, Y does the same job in 12 days